Math, asked by geethagiriarni81, 2 months ago

How many 5's are there in the following sequence such that the sum of the two immediately following digits is greater than the sum of two immediately preceding digits?
3 7 6 5 8 3 2 4 5 5 4 8 7 9 1 5 3 4 8 7 5 9 8 7 6 4
(A) One
(B) Two
(C) Three
(D) Four

Answers

Answered by godg13101
2

Answer:

5 are there

Step-by-step explanation:

Answered by praazhnaashres
2

Answer:

d its 4

Step-by-step explanation:

because in first 5 add 6 nad 7 its 13 and add 8 and 5 it's too 13 so first 5 not counted ok so answer is 4

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