How many 5's are there in the following sequence such that the sum of the two immediately following digits is greater than the sum of two immediately preceding digits?
3 7 6 5 8 3 2 4 5 5 4 8 7 9 1 5 3 4 8 7 5 9 8 7 6 4
(A) One
(B) Two
(C) Three
(D) Four
Answers
Answered by
2
Answer:
5 are there
Step-by-step explanation:
Answered by
2
Answer:
d its 4
Step-by-step explanation:
because in first 5 add 6 nad 7 its 13 and add 8 and 5 it's too 13 so first 5 not counted ok so answer is 4
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