Question

how many AG atoms are there in 0.0001 g of ag molar mass of of ag is 108 g per mole

Answer 1

0.0001g Ag 
= 1 mole of Ag/108g x 6.022 x 10²³ 
= 0.0557 x 10²³ Atoms
 hope it help

Answer 2

Given:

Mass of Ag = 0.0001g

Molar mass of Ag = 108g/mol

To find:

Number of atoms = ?

Calculation:

As Molar mass of Ag is 108g/mol, it means that

108g/mol = 6.023 ×$10^{23}$ atoms

∴ 0.0001 g = x atoms

When the equations are cross multiplied, it gives as:

x = $\frac{0.0001\times (6.022\times10^{23})}{108}$

x = $\frac{6.023\times 10^{19}}{108}$

x = 5.5768× $10^{17}$

Conclusion:

0.0001 g of Ag molar with mass of of 108 g per mole is composed of 5.5768× $10^{17}$ atoms.

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