Question

how many atom present in 5.6 gm KOH molecular weight is 56 gm
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Answer 1

Answer:

No. of moles = mass/molecular weight

no. of moles = 5.6/56

= 1/10 moles

No. of atoms in 1 mole

$= 6.022 \times 10 {}^{23} atoms$

So no. of atoms in 1/10 moles

$= \frac{1}{10} \times 6.022 \times 10 {}^{23} \\ = 6.022 \times 10 {}^{22} atoms$