Question

How many atoms and molecules present in 124 g of p4?

Answer 1

Atomic mass of phosphorus is 31.

But there are 4 atoms of phosphorus in one molecule of phosphorus.

So mass of 1 molecule of phosphorus =(4x31)amu. = 124 amu.

Given mass= 124 g

number of moles of phosphorus molecules = 124/124 = 1 mole.

One mole contains 6.023 x 10 ^ 23 particles.

So 124 g P4 contains 6.023 x 10^23 molecules

= 6.023x10^23 x 4 atoms

=24.092x 10^23 atoms of phosphorus.

Seems it helps. CHEERS!!!