Question

how many atoms are in 35.0 grams of sucrose, c12h22o11?

Answer 1

Question:

→how many atoms are in 35.0 grams of sucrose, c12h22o11?

Answer:

• 12 carbon atoms, 22 hydrogen atoms and 11 oxygen atoms.

Explanation:

→The subscripts also indicate the ratios of the elements. A dozen CO2 molecules have one dozen carbon atoms and two dozen oxygen atoms.

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Answer 2

The answer is 0.7875 × 10²³ atoms

GIVEN

Mass of C₁₂H₂₂O₁₁ = 35.0 grams

TO FIND

Number of atoms

SOLUTION

The above problem can be simply solved as follows;

Molar mass of C₁₂H₂₂O₁₁ = 342.3 g/mol

It is known that,

1 mole of substance = 6.022 × 10²³ of entities. = molar mass

Therefore,

342.3 grams of sucrose = 6.022 × 10²³ molecules

Number of molecules in 1 grams = (6.022 × 10²³)/342.3

= 0.0175 × 10²³ molecules

Now,

Number of atoms in 1 molecule of sucrose = 45 atoms

atoms in 0.0175 × 10²³ molecules = 45 × 0.0175 × 10²³

= 0.7875 × 10²³

Hence, The answer is 0.7875 × 10²³ atoms

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