Chemistry, asked by chellasubhashini, 11 months ago

how many atoms are present in 128 gram of ozone

Answers

Answered by Anonymous

1

Answer:

sol: O3

Molecular mass = 16×3 = 48

No. of mole : 128/ 48 = 2.66 mol

2.66mol atoms are present in 128 g of zone.

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