Question

how many atoms are present in 20 gram of sodium​

Answer 1

Answer:

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Answer 2

Explanation:

molar mass of sodium (Na) =23g

given mass =20g

1 mole of Na=23g

1 mole of Na=6.022*10^23 atoms.

therefore,

23g of Na=6.022*10^23atoms

1g=6.022*10^23/23

20g=6.022*10^23/23*20

=0.261*10^23*20

=0.522*10^23

=5.22*10^22 atoms

therefore in 20g of sodium 5.22*10^23 atoms are present.