How many atoms are present in 480 g of Ozone
Answers
Answered by
6
Molar mass of Ozone = 3 * 16 = 48.
so 48 g of Ozone contains 1 mole of ozone molecules.
1 mol = 6.022 * 10²³
so 480 g of ozone contains 10 moles of ozone.
So 10 moles of ozone contains 6.022 * 10²³ * 10
= 6.022 * 10²⁴
so 48 g of Ozone contains 1 mole of ozone molecules.
1 mol = 6.022 * 10²³
so 480 g of ozone contains 10 moles of ozone.
So 10 moles of ozone contains 6.022 * 10²³ * 10
= 6.022 * 10²⁴
thank You
Answered by
1
Answer:
10
Explanation:
it is correct answer
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