Question

how many atoms are present in 5.4 of silver

Answer 1

108 g of Ag contain 6.022×10*23 atoms
5.4g will contain=6.022×10*23×5.4/108
=32.51×10*23/108
3.01×10*22 atoms.
mark BRAINLIEST.

Answer 2

given mass of silver =5.4 gm

atomic mass of silver=108

moles=1/20

$use \: concept \\ moles = \frac{no.of \: particles}{avogadro \: no.} \\ \frac{1}{20} = \frac{x}{6.022 \times {10}^{23} } \\ x = \frac{6.022 \times {10}^{23} }{20} \\ x = 3.011 \times {10}^{22}$
hope it will help you.