Question

The quantity of electricity required to deposits 127.08gm of cupper is

Answer 1

1 Faraday (96,500 Coulombs) of charge is required to deposit 1 gram equivalent of any metal.

The gram equivalent weight of copper = Atomic weight/Valency

= 63.54/2 = 31.77 grams

So, 1 faraday of charge is required to deposit 31.77 grams of copper,

Quantity of charge required to deposit 127.08 grams = 127.08/37.77 = 4

Thus, 4 Faraday of charge is required to deposit 127.08 grams of Copper.

Hope it helps!!