Question

how many atoms are present in 8.875 g of chlorine​

Answer 1

Answer:1.505×10^23

Explanation:

No. Of moles of chlorine =8.875/35.5=0.25

No. Of atoms =0.25×6.022×10^23

=1.505×10^23

Answer 2

Answer:

1.5×10^23 atoms of Cl

Explanation:

No. of moles of Cl=8.875 ÷35.5=0.25

Now, No of atoms = 0.25 × avogadro no. =0.25×6×10^23

1.5×10^23 atoms of Cl