How many atoms are present in 9.0g of aluminium amd 0.8g of iron.?( given atomic mass of Al=27amu and Fe=56amu)
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one atom of aluminium equals to 27 grams 0.9 grams of aluminium can have one third
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Answer:
No. Of moles =GMU/molar mass
0.8/56=0.014moles
No.of atoms=no. Of moles×avagadros number
0.014×6.022×10^23
Explanation:
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