Question

How many atoms are present in each of the following: (i) 252 g of C? (ii) 0.01 mole of aluminum? A. 24.08×10^23 and 6.022×10^21 B. 22.32×10^23 and 6.022×10^23 C. 24.08×10^23 and 6.022×10^25 D. 20.92×10^23 and 6.022×10^25 ​

Answer 1

Answer:

(i) 21

(ii) C

Explanation:

(i) due to :

RAM = Mass of one atom of the element / (1/12) Mass of one atom of carbon ( C _12)

(ii) according to mole concept