How many atoms of Bi are there in a 41.8 g sample?
Answers
Answered by
7
Answer:
You can calculate it by the avagardos number
Answered by
7
Answer:
The number of particles in the 41.8g sample of Bismuth is 12.044 × 10²³
Explaination:
Bismuth atomic mass ≈ 209u
Molar mass of Bismuth ≈ 209g
Avogadro's number ≈ 6.022 x 10²³
1 mole = given mass/molar mass
therefore 418/209 × 10 = 0.2 moles of bismuth
to find the no. of particles
no. of particles = x
1 mole = no. of particles/avogadro no.
therefore substituting values gives
0.2 = x/6.022 × 10²³
hence
2/10 × 6.022 × 10²³ = x
12.044 × 10²³ = x
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