Chemistry, asked by waltonjillian21, 10 months ago

How many atoms of Bi are there in a 41.8 g sample?

Answers

Answered by 7777777RAM
7

Answer:

You can calculate it by the avagardos number

Answered by akshatsingh9097
7

Answer:

The number of particles in the 41.8g sample of Bismuth is 12.044 × 10²³

Explaination:

Bismuth atomic mass ≈ 209u

Molar mass of Bismuth ≈ 209g

Avogadro's number ≈ 6.022 x 10²³

1 mole = given mass/molar mass

therefore 418/209 × 10 = 0.2 moles of bismuth

to find the no. of particles

no. of particles = x

1 mole = no. of particles/avogadro no.

therefore substituting values gives

0.2 = x/6.022 × 10²³

hence

2/10 × 6.022 × 10²³ = x

12.044 × 10²³ = x

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