how many atoms of each element are present there in 300g of CaCO3
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Molecular mass of CaCO3 = 40 + 12 + 48 =100g
1 mole of CaCO3 contains 3 mole of oxygen atoms
Also,100 g of Calcium carbonate contains 3 X 6.022 X 1023 oxygen atoms
=> 300g of Calcium carbonate contains
= 300 X 3 X 6.022 X 1023/ 100 = 54.205 X 10^23 oxygen atoms
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