Chemistry, asked by jbenefield21, 1 month ago

How many atoms of N are in 137.0 grams of N2O3? A. 1.085 × 1023 B. 1.802 × 1023 C. 5.985 × 1023 D. 2.171 × 1024 E. 3.604 × 1024

Answers

Answered by Anonymous
2

Answer:

Option (d) is the correct answer.

Explanation:

It is given that mass of is 137.0 g. Molar mass of   is as follows.     Molar mass of   = 2 × 14 + 3 × 16                                                                 = 76 g Thus, number of moles will be calculated as follows.         No. of moles =                               =                               = 1.803 mol There are 2 nitrogen (N) atoms present in the formula of dinitrogen trioxide. Also Avogadro's number equals atoms or molecules per mol. Therefore, number of N molecules or atoms in is as follows.            Number of N atoms =                                              = atoms                                              = atoms Thus, we can conclude that there are atoms of N in in 137.0 grams of .

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