How many atoms of N are in 137.0 grams of N2O3? A. 1.085 × 1023 B. 1.802 × 1023 C. 5.985 × 1023 D. 2.171 × 1024 E. 3.604 × 1024
Answers
Answer:
Option (d) is the correct answer.
Explanation:
It is given that mass of is 137.0 g. Molar mass of is as follows. Molar mass of = 2 × 14 + 3 × 16 = 76 g Thus, number of moles will be calculated as follows. No. of moles = = = 1.803 mol There are 2 nitrogen (N) atoms present in the formula of dinitrogen trioxide. Also Avogadro's number equals atoms or molecules per mol. Therefore, number of N molecules or atoms in is as follows. Number of N atoms = = atoms = atoms Thus, we can conclude that there are atoms of N in in 137.0 grams of .
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