How many atoms of na are present in 115 Amu of Na?
Answers
Answered by
1
Answer:
Na or sodium has an atomic mass of 22.98977 so if we divide the mass of our sample 11.5 g by this number we get 11.5 / 22.98977 = 0.50022249 moles of sodium. 6.023 * 0.50022249 * 10^23 atoms = 3.0128 * 10^23 atoms.
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Answered by
1
Answer:
5 Na atoms are contained in 115 Amu of Na
Explanation:
As number of moles = given mass/molar mass
so no. of moles= 115/23=5 moles
1mole = 1 Na particles so 5 moles=5Na particles
YOU CAN NOW SOLVE IT BY USING Na = 6.022*10^23 AND GET YOUR FINAL ANSWER
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