How many atoms of oxygen are there in 18g of water?
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6.022×10 to the power 23
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Answer:Assuming 100% purity, there are 6.02214086 * 10^23 atoms of oxygen present in 18g of water.
Atomic weight of hydrogen is about 1, atomic weight of oxygen is almost 16. Water is H2O so it’s atomic weight is 1*2 + 16, that’s 18. Now devide 18g by 18 and you get 1, the number of moles of water in 18g of water. Then, multiply by the Avogadro’s constant (6.02214086 * 10^23 mol^-1) and you get the number of water molecules in those 18g (6.02214086 * 10^23 molecules). Since there’s one atom of oxygen in every water molecule, that’s also the number of oxygen atoms.
Explanation:
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