Question

How many atoms of the hydrogen are present in one molecule of the following compound :(NH4)2, SO4, NH3, NH2, CONH2

Answer 1

Answer:

1)6

2)0

3)2

4)2

r the no. of atoms present in the molecules

Answer 2

Answer:

The number of hydrogen atoms present in one molecule of the given compounds are :

i) 8

ii) 0

iii) 3

iv) 2

Explanation:

The number of Hydrogen atoms present in each molecule is calculated simply by counting the number of Hydrogen atoms present in the molecule.

I) The first molecule is Ammonia $(NH_{4} )_{2}$. In case of Ammonium the atoms that are present are Nitrogen and Hydrogen. The number of Hydrogen atoms in ammonium are:

Hydrogen atoms- 4 x 2 = 8

Therefore, 8 atoms of Hydrogen is present in Ammonia.

II) The second molecule is $SO_{2}$. Since there is no hydrogen atoms present in Sulphur-di-oxide, the number of Hydrogen atoms is 0.

III) The third compound is Ammonia $(NH_{3} )_}$. The number of Hydrogen atoms in Ammonia is given by

Hydrogen- 3 atoms

Therefore, there are 3 atoms of Hydrogen in Ammonia.

IV) The fourth compound is  $(NH_{2} )$. The number of Hydrogen atoms present is as follows:

Hydrogen- 2 atoms

Therefore, there are 2 hydrogen atoms in $(NH_{2} )$.

V) The last compound is $CONH_{2}$. The number of Hydrogen atoms is as follows:

hydrogen atoms-2

Therefore, there are 2 hydrogen atoms in $CONH_{2}$.

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