Question

how many atoms r in 52 gms of he

Answer 1

1 mole of He contains = 6.022 x 1023 particles = molar mass (4 g)

• ..No of atom in 52 gms
• HE= 52×6.022 × 10 *23 ÷ 4
• 78.28×10*23 atoms

.....

Answer 2

Answer:

1 mole of helium contains = 6.022*10^23 particles = molar mass (4 g)

= 52*6.022*10^23/4

=78.28*10^23 atoms....