Chemistry, asked by ahmedqadeerahme44642, 6 months ago

How many bond angels of 90 are present in trigonal bipyramidal shape of PCL5

Answers

Answered by sandeepsaini0

Explanation:

PCl5 has 6 bond angle of 90

Answered by santhoskmuthukumarv

Answer:

Example: PCl

The five sp3d hybrid orbitals are singly occupied . These hybrid orbitals overlap with singly filled 3pz atomic orbital of five Chlorine atom to form five sigma bond (P- Cl). Geometry of PCl5 molecule is trigonal bipyramidal. Bond angle is 900 and 1200.

Explanation:

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