Math, asked by iloveyou9847, 1 year ago

How many bricks,eachof dimensions 25cm ×16cm×10cm will be neededto build awall 24m long, 6cm high and 0.4 thick

Answers

Answered by Mercidez
2
\boxed{\boxed{\boxed{\bold{\green{Solution :\longrightarrow}}}}}

Dimensions \: \: of \: \: a \: \: single \: \: brick

Lenght \: (l) = 25 \: cm \\ \\ Breadth \: (b) = 16 \: cm

Height \: (h) = 10 \: cm

Volume = l \times b \times h \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = (25 \times 16 \times 10) \: {cm}^{3} \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 4000 \: {cm}^{3}

Again,

Dimensions \: \: of \: \: the \: \: wall \\ \\ Lenght \: (l) = 24 \: m = 2400 \: cm \\ \\ Breadth \: (b) = 6 \: cm \\ \\ Height \: (h) = 0.4 \: m = 40 \: cm

Volume = l \times b \times h \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = (2400 \times 6 \times 40) \: {cm}^{3} \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 576000

Required \: \: number \: \: of \: \: bricks

 = \frac{Volume \: \: of \: \: the \: \: wall}{Volume \: \: of \: \: a\: \: single \: \: brick} \\ \\ = \frac{576000 \: {cm}^{3} }{4000 \: {cm}^{3} } \\ \\ = 144

Hence, \: \: the \: \: required \: \: number \\ of \: \: bricks \: \: are \: \: 144.

\bold\red{\underline{Have \: \: a \: \: nice \: \: day.}}
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