Question

if sinA=1/2,find the value of 2secA/1+tan2A

Answer 1

If sin A = 1/2

Then by using pythagorus

2^2 = 1^2 + x^2

4 = 1 + x^2

X = root 3

Cos A = root3/2

2secA/1+tanA

1/cosA / 1+tanA

Root3/2 / 1+1/root3

3/3

1

Answer 2

Answer:

Step-by-step explanation:

If sin A = 1/2

Then by using pythagorus

2^2 = 1^2 + x^2

4 = 1 + x^2

X = root 3

Cos A = root3/2

2secA/1+tanA

1/cosA / 1+tanA

Root3/2 / 1+1/root3

3/3

1