Question

How many bricks will be required to construct a wall 8 m long, 6 m high and 22.5 cm thick if each brick measures (25 cm x 11.25 cm x 6 cm ) ?​

Answer 1

Question :–

How many bricks will be required to construct a wall of 8 m long, 6 m high and 22.5 cm thick, if each brick measures 25 cm x 11.25 cm x 6 cm ?

To Find :–

The Number of bricks required to construct the wall.

Given :–

Dimensions of the wall :-

• Length = 8 m
• Height = 6 m
• Width = 22.5 m

Dimensions of the Brick :-

• Length = 25 cm
• Breadth = 6 cm
• Height = 11.25 cm

We know :–

Volume of a cuboid :-

$\underline{\boxed{\bf{V = l \times b \times h}}}$

Where :-

• V = Volume of the Cuboid.

• l = Length of the Cuboid.

• b = Breadth of the Cuboid.

• h = Height of the Cuboid.

Concept :–

According to the Question , we have to find the no. of bricks required to construct the wall .

So, the volume of one brick divided by the volume of the wall will give the no. of bricks required to build the wall.

Solution :–

Volume of the wall :-

Given :-

• l = 8 m

• b = 6 m

• h = 22.5 cm

Now , let's convert the 8 m and 6 m in cm by multiplying it by 100 , we get :-

• l = 8 m

==> l = (8 × 100) cm

==> l = 800 cm

Hence, the length of the wall is 800 cm.

• b = 6 cm

==> b = (6 × 100) cm

==> b = 600 cm

Hence, the breadth of the wall is 600 cm.

Now , Using the Formula for volume of a Cuboid and by substituting the values in it , we get :-

$:\implies \bf{V = l \times b \times h} \\ \\ \\ :\implies \bf{V = 800 \times 600 \times 22.5} \\ \\ \\ :\implies \bf{V = 10800000} \\ \\ \\ \therefore \purple{\bf{V = 10800000 cm^3}}$

Hence, the volume of the wall is 10800000 cm³.

Volume of on brick :-

Given :-

• l = 22.5 cm

• b = 11.25 cm

• h = 6 cm

Now , Using the Formula for volume of a Cuboid and by substituting the values in it , we get :-

$:\implies \bf{V = l \times b \times h} \\ \\ \\ :\implies \bf{V = 25 \times 11.25 \times 6} \\ \\ \\ :\implies \bf{V = 1687.5} \\ \\ \\ \therefore \purple{\bf{V = 1687.5 cm^3}}$

Hence, the volume of one brick is 1687.5 cm³.

No. of bricks required to construct the wall :-

$:\implies \bf{No.\:of\:brick = \dfrac{Volume\:of\:wall}{Volume\:of\:one\:brick}} \\ \\ \\ :\implies \bf{No.\:of\:brick = \dfrac{10800000}{1687.5}} \\ \\ \\ :\implies \bf{No.\:of\:brick = 6400} \\ \\ \\ \therefore \purple{\bf{No.\:of\:brick = 6400}}$

Hence, the no. of bricks required to build the wall is 6400.

Answer 2

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