how many carbon atoms present in 1.4 g of c2h4?
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a) Mass of ethylene gas = 1.4 g Number of molecules is 0.05 mole ethylene = C2H2 = mass/molar mass = 1.4/28 = 0.5 Number of molecules in 0.05 mole ethylene = 0.05 x 6 x 1023 = 3 x 1022 molecules 1 mole of ethylene has volume at s.t.p. = 22.4 lit. Volume occupied by 0.05 moles of ethylene gas at s.t.p. = 0.05 x 22.4 = 112 lit. (b) Vapour density of ethylene = mol.wt/2 = 28/2 = 14
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