How many charge is required for the reduction of 1 mole of cu 2 + 2 cu?
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Explanation:
The oxidation state of Mn on the left hand side of the equation is +7, and it is +2 on the RHS. 1 mole of electrons carries 1 Faraday, or 96,485 C charge. So, 5 moles of electrons will carry 5*96,485 = 485,425 C of charge. Here, 1 mole of MnO4– requires 5 moles of electrons to give 1 mole of Mn2+.
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