How many even 3 digit number can be formed from the digits 1 2 5 6 and 9 without repeating any of the digits?
Answers
Answered by
0
Answer:
12569
Step-by-step explanation:
Phale ham 1 no. Lege bhir ham 2 no. Lege bhir ham 5 no. Lege bhir ham 6 no. Lege bhir ham 9 no. Lege
Answered by
3
Answer:
Step-by-step explanation:
No of possible with 2 at one' s
=No of remaining digits=4
These 4 digits can be placed at 2 places by ways
=ā“Pā=4!/!(4-2)
=4*3*2*1/1*2
=4*3=12
similarly
No of possible with 6 at one' s=12
Hence total no=12+12=24
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