How many coin-shaped solids of 1 cm radius and 0.2 cm thickness can be made by melting a solid metal bricks of length 16cm width 11cm and height 10cm
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Answered by
10
volume of metal brick = l× b× h
=16× 11 × 10
= 1760 m cube
now, volume of 1 coin = πr sq. h
here r= 1cm and h=0.2 cm
taking π =3.14
volume of coin = 3.14× 1× 0.2
= 0.628 cm
no. of coins = volume of metal brick/volume of one coin
= 1760/0.628
= 2803 (approximately)
=16× 11 × 10
= 1760 m cube
now, volume of 1 coin = πr sq. h
here r= 1cm and h=0.2 cm
taking π =3.14
volume of coin = 3.14× 1× 0.2
= 0.628 cm
no. of coins = volume of metal brick/volume of one coin
= 1760/0.628
= 2803 (approximately)
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Answered by
10
Volume of brick = 10×11×16=1760
Height is to be found
22/7 r^2 h = 1760
22/7×1×1×h = 1760
22/7×h = 1760
h = 1760×7/22 = 560
No.of coins = 560÷0.2 = 2800 coins
Height is to be found
22/7 r^2 h = 1760
22/7×1×1×h = 1760
22/7×h = 1760
h = 1760×7/22 = 560
No.of coins = 560÷0.2 = 2800 coins
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