How many coin-shaped solids of 1 cm radius and 0.2 cm thickness can be made by melting a solid metal brick of length 16 cm,width 11 cm and height 10cm ?
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1
cyclinder= 22/7 . 1^2 . o.2=0.628571429
cuboid = l. b. h
= 16. 11. 10
= 1760
dividing the s.A
=1760÷ 0.628571429
= 2799.999998091
cuboid = l. b. h
= 16. 11. 10
= 1760
dividing the s.A
=1760÷ 0.628571429
= 2799.999998091
shivavs:
ur wish to take pi value
Answered by
2
Given, dimensions of the solid brick are 16 cm, 11 cm and 10 cm.
Volume of the brick = (16×11×10) cm³
Radius of coin shaped solid, r = 1 cm
its thickness, h = 0.2 cm.
Volume of each coin shaped solid = πr²h = (3.14 ×1×1×0.2 ) cm³
Let the number of such solids be x.
so, x × Volume of each solid = volume of brick
=> x × 3.14 ×1×1×0.2 = 16×11×10
=> x = (16×11×10) / 3.14×0.2
=> x = 2816
Therefore, 2816 coin shaped solids can be made by melting the solid brick.
Volume of the brick = (16×11×10) cm³
Radius of coin shaped solid, r = 1 cm
its thickness, h = 0.2 cm.
Volume of each coin shaped solid = πr²h = (3.14 ×1×1×0.2 ) cm³
Let the number of such solids be x.
so, x × Volume of each solid = volume of brick
=> x × 3.14 ×1×1×0.2 = 16×11×10
=> x = (16×11×10) / 3.14×0.2
=> x = 2816
Therefore, 2816 coin shaped solids can be made by melting the solid brick.
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