How many consecutive numbers are added to get sum 325?
Answers
Answer:
(n / 2)(first number + last number) = sum, where n is the number of integers. Let's use the example of adding the numbers 1-100 to see how the formula works.
Step-by-step explanation:
HEY MATE ..
Here we will use algebra to find three consecutive integers whose sum is 325. We start by assigning X to the first integer.
Since they are consecutive, it means that the 2nd number will be X + 1 and the 3rd number will be X + 2 and they should all add up to 325.
Therefore, you can write the equation as follows:(X) + (X + 1) + (X + 2) = 325
To solve for X,
you first add the integers together and the X variables together. Then you subtract three from each side, followed by dividing by 3 on each side. Here is the work to show our math:
X + X + 1 + X + 2 = 3253X + 3 = 3253X + 3 - 3 = 325 - 33X = 3223X/3 = 322/3X = 107 1/3
Since 107 1/3 is not an integer, there is no true answer to this problem.
However, there are three numbers that add up to 325.
The first number is (107 1/3), the second number is (107 1/3) + 1, and the third number is (107 1/3) + 2.
Therefore, we could make this the answer to "Three consecutive numbers that add up to 325 are?":107 1/3 + 108 1/3 + 109 1/3 = 325
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