Question

how many coulombs of electricityhow many columns of electricity required for the following reduction processes one mole of silver positive​

Answer 1

Weight/eq wt= Q/F

Eq wt = molar mass /n Factor

Reduction of Ag+

Ag+. + e-. ------> Ag

No of electron exchanged =n Factor=1

Moles of Ag=1

Weight/molwt×n Factor=Q/F

Moles×n Factor = Q/F

1×1×F=Q

Q=96500C

I hope this helps ( ╹▽╹ )