How many cubic centimeter of iron is required to construct an open box whose external dimensions are 36cm,25cm, and 16.5 cm provided the thickness of the iron is 1.5cm. If one cubic cm of iron weighs 7.5g find the weight of the box.
Answers
Answered by
25
Volume of External dimensions = 36cm * 25cm * 16.5 cm =14850 cm cube
Internal Volume = (36-3) * (25-3)* (16.5 -1.5) =
33 * 22 * 15 =10890 cm cube
Volume of metal = External Volume - Internal Volume=14850-10890=3960 cm cube
∴The weight of the box = 3960 cm cube 7.5=29700g= 29.7kg
Internal Volume = (36-3) * (25-3)* (16.5 -1.5) =
33 * 22 * 15 =10890 cm cube
Volume of metal = External Volume - Internal Volume=14850-10890=3960 cm cube
∴The weight of the box = 3960 cm cube 7.5=29700g= 29.7kg
Answered by
7
HERE'S YOUR ANSWER
Volume of External dimensions = 36cm * 25cm * 16.5 cm =14850 cm cube
Internal Volume = (36-3) * (25-3)* (16.5 -1.5) =33 * 22 * 15 =10890 cm cube
Volume of metal = External Volume - Internal Volume=14850-10890=3960 cm cube
∴The weight of the box = 3960 cm cube 7.5=29700g= 29.7kg
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