Question

How many d- electrons in C u^{+}(Cu + ( At. \mathrm{No}=29)No=29) can have the spin quantum number \left(\frac{-1}{2}\right) ?( 2 −1 ​ )?

Answer 1

ANSWER

ANSWERThe electronic configuration of Cu

ANSWERThe electronic configuration of Cu +

ANSWERThe electronic configuration of Cu + is [Ar]3d

ANSWERThe electronic configuration of Cu + is [Ar]3d 10

ANSWERThe electronic configuration of Cu + is [Ar]3d 10 . It has ten d electrons. Out these, one half, i.e, 5 will have the spin quantum number (−

ANSWERThe electronic configuration of Cu + is [Ar]3d 10 . It has ten d electrons. Out these, one half, i.e, 5 will have the spin quantum number (− 2

ANSWERThe electronic configuration of Cu + is [Ar]3d 10 . It has ten d electrons. Out these, one half, i.e, 5 will have the spin quantum number (− 21

ANSWERThe electronic configuration of Cu + is [Ar]3d 10 . It has ten d electrons. Out these, one half, i.e, 5 will have the spin quantum number (− 21

ANSWERThe electronic configuration of Cu + is [Ar]3d 10 . It has ten d electrons. Out these, one half, i.e, 5 will have the spin quantum number (− 21 ) and the remaining half will have the spin quantum number (+

ANSWERThe electronic configuration of Cu + is [Ar]3d 10 . It has ten d electrons. Out these, one half, i.e, 5 will have the spin quantum number (− 21 ) and the remaining half will have the spin quantum number (+ 2

ANSWERThe electronic configuration of Cu + is [Ar]3d 10 . It has ten d electrons. Out these, one half, i.e, 5 will have the spin quantum number (− 21 ) and the remaining half will have the spin quantum number (+ 21

ANSWERThe electronic configuration of Cu + is [Ar]3d 10 . It has ten d electrons. Out these, one half, i.e, 5 will have the spin quantum number (− 21 ) and the remaining half will have the spin quantum number (+ 21

ANSWERThe electronic configuration of Cu + is [Ar]3d 10 . It has ten d electrons. Out these, one half, i.e, 5 will have the spin quantum number (− 21 ) and the remaining half will have the spin quantum number (+ 21 ).