Question

How many degrees are there in an angle which equals 1/6 th of its supplement

Answer 1

let one suplement x and second 180-x
according to question ,
x=(180-x)/6

6x=180-x

7x=180

x=180/7 and second 180-x =180-x=180-180/7=180 x 6/7=1080/7

Answer 2

Let the supplement be x
Then the angle = 1/6x

A/Q,
x + 1/6x = 180 ..........since the angles are supplementary
(6x + x)/6 = 180
7/6x = 180
x = 180 x 6/7
x = 1080/7°

The required angle = 1/6 x 1080/7 = 180/7°