Question

How many different 5-digit numbers can be formed from the digits 9, 0, 4, 1, 6, so that '0' is in the tenth place? (all the digits must be used)

Answer 1

The numbers may be

94106, 64901

91406, 69401

91604, 64109

96104, 61409

96401, 61904

94601,69104

41609, 46109

49106

41906

46901

49601

14609

16409

19406

14906

19604

16904

24 combinations are possible

Answer 2

Answer:

digits 0, 1, 4, 6, 7, and 9 without repetition?

In total 600 five digit numbers can be formed by using 0,1,4,6,7, and 9.

Explanation :—

First digit can be 1,4,6,7 and 9. Total 5 ways to choose that number. (For example We took 9)

Second digit can be 0,1,4,6 and 7. Total 5 ways to choose ( This time take any number)

For third fourth and fifth digit number of ways to choose a number is 4, 3 and 2 ways.

So in total 5*5*4*3*2 ways = 600 ways to form a five digit number without any repetition.

With repetition it is 5*6*6*6*6 as any digit can come any time but for first digit we took 5 because we can't form a five digit number starting with zero as it will be a four digit number.

So, without repetition answer is 600 ways and with repetition answer will be 6480 ways