how many different code words are there such that two distinct english alphabets are followed by two distinct non-zero digits? how any of them end in an odd integer?
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Answered by
0
Answer:
I do not under stand your question
Answered by
1
Answer:
46800
Step-by-step explanation:
There are in all 26 English alphabets. We have to choose 2 distinct alphabets.
First alphabet can be selected in 26 ways. Second alphabet can be selected in 25 ways. Again out of 9 Digits (1 to 9), first digit can be selected in 9 ways. second digit can be selected in 8 ways.
Thus, the number of distinct codes
=26×25×9×8
=46800
hope this helps you ❤️
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