how many different types of gametes can be formed by f1 progeny resulting from the following cross AABBCC ×aabbcc also state the reason
a) 3
b)8
c)27
d)64
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Answered by
41
A cross b/w AABBCC and aabbcc gives the result : AaBbCc
F1 :AaBbCc
We know, types of gametes is given by 2^n
Where n= no of heterozygous .
Here n=3
So no of gametes: 2^3=8 ie. option(b)
A few other useful formulae attached.
F1 :AaBbCc
We know, types of gametes is given by 2^n
Where n= no of heterozygous .
Here n=3
So no of gametes: 2^3=8 ie. option(b)
A few other useful formulae attached.
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Answered by
6
option ➡️ b) 8
Hope this helps ☺️☺️☺️
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