How many different ways are there to pain ‘n’ balls with 4 colors ( A, B, C, D). The number of balls in color A must be odd. The number of balls in color B must be even. (includes 0)
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Answer:
mark brainliest please
Step-by-step explanation:
got em annadu you want it now I am going to do the work of 88h I was in bed all weekend long to
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Answer:
This is known as the coupon collector's problem.
The average number of tries needed to see each of 4 colors is
44+43+42+41=813
The terms are 4/4 for the time to take one ball; then 4/3 for the average time it takes after the first ball until you see another code; 4/2 for the average time it takes after the first time you see the second color until you see a third, and finally 4/1 for the time you then have to wait until you see the last color. (These can just be added due to the additivity of expectations).
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