Question

How many different ways can the letters of ​"accessory" be​ arranged?

Answer 1

Answer:

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Step-by-step explanation:

The number of permutations of a string of n distinct characters is n!, but if there is a set of duplicate characters of size m, this divides the number of permutations by m!.

In this case, we have a string of 9 characters, with two pairs of duplicates, so the number of permutations is 9!/(2!2!) = 90720