Math, asked by charan7465, 1 year ago

How many different word can be formed from the letter of the words 'interference' if no two consonant are to be together?

Answers

Answered by writersparadise
37
Since the options are not given,  I am giving a general answer.

There are 5 vowels in the 'Interference', i.e,  - I, e, e, e, e.

There are 7 consonants in the word - N, T, R, F, R, N, C.

So if no two consonants should be together, then it should be placed in between the vowels. So, only 6 consonants can be placed that way. But there are 7 consonants in the given word. So, there should be at least 1 instance where 2 consonants will come together. Else, there will be no words formed when two consonants should not be together.
Answered by anvitha96
5

Step-by-step explanation:

It is not possible having no consonant together .It can’t be done. It’s impossible. Interference has 5 vowels and 7 consonants.

Suppose you have 5 apples and 7 oranges. Can you put them in a row that alternates between apples and oranges? Nope. Try starting the row with an orange, then add an apple, then an orange. And keep going. Eventually you have a row with 5 apples and 6 oranges. You have nowhere to put the seventh orange.

The same holds for 5 vowels and 7 consonants

If there are options having none then none is correct option.

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