Question

how many digits will be there in product of 2^32*5​

Answer 1

Answer:

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Step-by-step explanation:

SOLUTION:SINCE 2^23×5^24×7^3=(2×5)^23×5×7^3=10^23=1,715 , we see that product in the number 1,715 followed by 23 zeros. Therefore, there are 4+23=27 digits in the product.

Answer 2

Answer:

The answer according to me will be 21,474,836,480

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