How many distinct sets of 3 positive integers have a mean of 6,a median of 7,and no maode
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Given mean=6, median=7, no mode
Let the three positive integers be x, x+1, x+2
Now mean = (x+x+1+x+2)/3 = (3x+3)/3 = x+1
But here x+1=6 i.e., x=5 ... which means we have 5 sets of numbers whose mean is 6. (But this is just for knowing the number of sets, we can't use it further) , and also from definition of mean
Mean= sum/ total number of integers... i.e.,
we get that sum= mean*total no. Of integers = 6*3=18
As median given is 7 and we have only 3 intergers in the set .. we can know that middle number is 7 ..i.e., the number set is :
0+7+11=18
1+7+10=18
2+7+9=18
3+7+8=18
5+7+6=18
As there is no mode we cant get the set (4+7+7)
Step-by-step explanation:
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