How many electron are present in 16 g of methane
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6.022 × 10^23 electron
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Formula for methane is CH4.
It means molecular weight of CH4 is 12+4 g.
It means there is 1 mole of methane.
This implies, there will be electrons equal to Avogadro constant i.e., 6.022*10^23.
It means molecular weight of CH4 is 12+4 g.
It means there is 1 mole of methane.
This implies, there will be electrons equal to Avogadro constant i.e., 6.022*10^23.
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