How many electron r in 3.1 mg of NO3
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NO. OF ELECTIONS =NO. OF MOLES OF NO3 X Avogadro no.
=[3.1x.001/62]x Na =0.00005Na [Na = Avogadro no]
HOPE IT HELPS U
=[3.1x.001/62]x Na =0.00005Na [Na = Avogadro no]
HOPE IT HELPS U
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