how many electrons are flowing per second past a point in a circuit in which there is a current of 4 ampere
Answers
Answered by
13
Answer:
2.5 × 10^19
Explanation:
Q = it
= 4 × 1
= 4 Columb
Q = ne
n = Q/e
= 4/ (1.6 × 10 ^ -19)
= 2.5 × 10^19
Answered by
2
Explanation:
Given,
I=4A
t=1sec
A/Q
q=it
= 4×1
= 4C
Now,
q=ne
as we know that
e=1.6×10^-19
so,
n=q/e
=4/1.6×10^-19
=2.5×10^19
- Hope it helps you
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