Physics, asked by piyush1251, 10 months ago

how many electrons are flowing per second past a point in a circuit in which there is a current of 4 ampere

Answers

Answered by hero50
13

Answer:

2.5 × 10^19

Explanation:

Q = it

= 4 × 1

= 4 Columb

Q = ne

n = Q/e

= 4/ (1.6 × 10 ^ -19)

= 2.5 × 10^19

Answered by anshu5991
2

Explanation:

Given,

I=4A

t=1sec

A/Q

q=it

= 4×1

= 4C

Now,

q=ne

as we know that

e=1.6×10^-19

so,

n=q/e

=4/1.6×10^-19

=2.5×10^19

  • Hope it helps you
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