Question

how many electrons are flowing per second past a point in a circuit in which there is current of 5 amp?

Answer 1

use this formula

I=$= \frac{q}{t}$

and q=ne

so

I=$\frac{ne}{t} \\ \\ it \: is \: said \: per \: second \: so \: t = 1$

I=$\frac{ne}{1} \\ 5 = n(1.6 \times {1.6}^{ - 19} ) \\ n = \frac{5}{1.6 \times {10}^{ - 19} } \\ n = \frac{5 \times {10}^{19} }{1.6}$
hope it will help you.

Answer 2

I=ne/t
n=It/e
n =5×1/1.6×10^-19
n=0.31×10^18
n=3.1×10^17
if right then please mark me brainliest