Question

*how many electrons are involved in decomposition of 1mol H₂O₂ in the reaction
H₂O₂ → H₂O + O₂*​

Answer 1

Answer:

1.08396 × 10²⁵ electrons

Explanation:

the equation is not balanced

so the balanced chemical equation: 2H₂O₂ → 2H₂O + O₂

H₂O₂ contains 2(1) + 2(8) = 18 electrons

since the reactants and products should have the same electron number,

6.022 × 10²³ × 18 electrons are involved

= 108.396 × 10²³ electrons

Answer 2

Answer:

It is a disproportionation reaction and the n-factor of a disproportionation reaction is given by the formula-

n

=

(

n

1

∗

n

2

)

/

(

n

1

+

n

2

)

where n1 → n-factor for oxidation reaction only ,ignoring that reduction of the same species is also occurring

And n2 →n-factor for reduction reaction only ,ignoring that oxidation of the same species is also occurring

Which comes 1 here. And n factor is no. of electrons transferred. So ans is 1.

Explanation: