*how many electrons are involved in decomposition of 1mol H₂O₂ in the reaction
H₂O₂ → H₂O + O₂*
Answers
Answer:
1.08396 × 10²⁵ electrons
Explanation:
the equation is not balanced
so the balanced chemical equation: 2H₂O₂ → 2H₂O + O₂
H₂O₂ contains 2(1) + 2(8) = 18 electrons
since the reactants and products should have the same electron number,
6.022 × 10²³ × 18 electrons are involved
= 108.396 × 10²³ electrons
Answer:
It is a disproportionation reaction and the n-factor of a disproportionation reaction is given by the formula-
n
=
(
n
1
∗
n
2
)
/
(
n
1
+
n
2
)
where n1 → n-factor for oxidation reaction only ,ignoring that reduction of the same species is also occurring
And n2 →n-factor for reduction reaction only ,ignoring that oxidation of the same species is also occurring
Which comes 1 here. And n factor is no. of electrons transferred. So ans is 1.
Explanation: