Question

If the dot product of two vectors A and B is A what is reason?
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Answer 1

Answer:

dot product

Explanation:

a.b = b.a

now this dot product is helpful for vectors

if a.b = b.a then a.b = a

Answer 2

Answer:

The scalar or dot product of two non-zero vectors \( \vec{a} \) and \( \vec{b} \), denoted by \( \vec{a} \).\( \vec{b} \) is

The scalar or dot product of two non-zero vectors \( \vec{a} \) and \( \vec{b} \), denoted by \( \vec{a} \).\( \vec{b} \) is\( \vec{a} \).\( \vec{b} \) = |\( \vec{a} \)| |\( \vec{b} \)| \( \cos \theta \)

The scalar or dot product of two non-zero vectors \( \vec{a} \) and \( \vec{b} \), denoted by \( \vec{a} \).\( \vec{b} \) is\( \vec{a} \).\( \vec{b} \) = |\( \vec{a} \)| |\( \vec{b} \)| \( \cos \theta \)where \( \theta \) is the angle between \( \vec{a} \) and \( \vec{b} \) and 0 ≤ \( \theta \) ≤ \( \pi \) as shown in the figure below.

The scalar or dot product of two non-zero vectors \( \vec{a} \) and \( \vec{b} \), denoted by \( \vec{a} \).\( \vec{b} \) is\( \vec{a} \).\( \vec{b} \) = |\( \vec{a} \)| |\( \vec{b} \)| \( \cos \theta \)where \( \theta \) is the angle between \( \vec{a} \) and \( \vec{b} \) and 0 ≤ \( \theta \) ≤ \( \pi \) as shown in the figure below.dot product

The scalar or dot product of two non-zero vectors \( \vec{a} \) and \( \vec{b} \), denoted by \( \vec{a} \).\( \vec{b} \) is\( \vec{a} \).\( \vec{b} \) = |\( \vec{a} \)| |\( \vec{b} \)| \( \cos \theta \)where \( \theta \) is the angle between \( \vec{a} \) and \( \vec{b} \) and 0 ≤ \( \theta \) ≤ \( \pi \) as shown in the figure below.dot productIt is important to note that if either \( \vec{a} \) = \( \vec{0} \) or \( \vec{b} \) = \( \vec{0} \), then \( \theta \) is not defined, and in this case

The scalar or dot product of two non-zero vectors \( \vec{a} \) and \( \vec{b} \), denoted by \( \vec{a} \).\( \vec{b} \) is\( \vec{a} \).\( \vec{b} \) = |\( \vec{a} \)| |\( \vec{b} \)| \( \cos \theta \)where \( \theta \) is the angle between \( \vec{a} \) and \( \vec{b} \) and 0 ≤ \( \theta \) ≤ \( \pi \) as shown in the figure below.dot productIt is important to note that if either \( \vec{a} \) = \( \vec{0} \) or \( \vec{b} \) = \( \vec{0} \), then \( \theta \) is not defined, and in this case\( \vec{a} \).\( \vec{b} \) = 0

Explanation:

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