How many electrons are present in1.6 g of methane
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Answer:
total number of electrons present in 1.6 g of methane. 6.022×1022 molecules of methane contain electrons =6.022×1022×10=6.022×1023.
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Explanation:
In 1 mole of methane ,electron present are 6.023×10²³
In 16g of methane will also have. 6.023× 10²³ ( 1mole = molecular mass)
therefore 1.6g of methane will contain. 6.023×10²³/16. * 1.6
6.023×10²³×0.1 = 6.023×10²² atoms
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