Question

How many electrons are required to construct 300 c
of charge

Answer 1

1electron-> 1.6×(10)^-19

1 coloumb=1/1.6×(10)^-19

1coloumb= 6.25×10^18

300coloumb = 300×6.25×10^18

=1875.00×10^18

=1875×10^18...

Answer 2

According to quantization of charge,

Q = ne

Where, n= number of electrons

Q = total charge on atom

e = charge on electron = 1.6×10-¹9 C

So, Q = 300C ( given)

As, Q = ne & n = ?

n = Q/e = 300/1.6×10-¹9

n = 1.875×10¹7

(Note :- in this answer, 10-¹7 = 10 raise to power minus 17)